### 4-3 How Derivatives Affect the Shape of a Graph

In this section, we learned how to use information about to give us information about .

**Increasing/Decreasing Test**

Since represents the slope of the curve at the point , tells us when the function is increasing or decreasing. The Mean Value Theorem we learned earlier leads to the conclusions:

1. When is positive, is increasing.

2. When is negative, is decreasing.

We can use these two statements to test whether a function is increasing or decreasing based on the first derivative. Hence, the name “Increasing/Decreasing Test”.

**The First Derivative Test**

We can also use the first derivative to find the local maximum and minimum of the graph of the function.

We first find the critical numbers of the function. Critical numbers are the x-values in the domain of a function when the derivative is zero or undefined. To find the critical numbers, set and solve for x.

Once the critical numbers have been found, determine whether each critical number is a local maximum, a local minimum, or neither. To do so, draw a number line, mark the number line , and mark the critical numbers on the line.

We know that is equal to zero at the critical numbers. Using the number line, we can find the sign changes for each critical number. These sign changes determine the nature of each critical number. This is called the First Derivative Test:

1. If the sign of changes from positive to negative at a critical value, then has a local maximum at that x-value.

2. If the sign of changes from negative to positive at a critical value, then has a local minimum at that x-value.

3. If does not change sign at a critical value, then there is neither a local minimum nor a local maximum at that x-value.

**Example**

For , (a) Find the critical values & identify each as a local maximum, minimum, or neither. (b) State the intervals where is increasing.**Solution**

Here is an example in which we use the Increasing/Decreasing Test and the First Derivative Test.

(a)

Now that we have the critical values, we create a number line and plot those values.

Using the First Derivative Test, we conclude the following:

Since changes from + to – at , is a local maximum

Since changes from – to + at , is a local minimum

(b) Since is positive on the intervals to the left of -2 and to the right of 0, is increasing on the intervals and .

**Concavity & The Second Derivative**

The first derivative of a function helps determine the local maximum and minimum and also tells where the function is increasing or decreasing. The second derivative tells us about the shape of the curve, its

**concavity,**and also gives us the

**Concavity Test**.

Look at Curve #1 below. In the graph, the slopes of the tangent lines change from negative to zero to positive. Therefore, the slope of the tangent, , is increasing. When a function is increasing, the derivative of , that is , is positive. This type of shape is **concave up**.

Look at Curve #2 below. In the graph, the slopes of the tangent lines change from positive to zero to negative. Therefore, the slope of the tangent, , is decreasing. When a function is decreasing, the derivative of , that is , is negative. This type of shape is **concave down**.

In Curve #1, there is a local minimum. In Curve #2, there is a local maximum. This gives us the **Second Derivative Test**:

If c is a critical number of , and

, then there is a local minimum at c.

, then there is a local maximum at c.

The Second Derivative Test is easy to use, but it is also limiting because there is no conclusion when . In that case, use the First Derivative Test, which can be applied in every case.

**Points of Inflection**

Points of inflection are points where the concavity of a function changes. Points of inflection are at values in the domain of a function where changes sign from positive to negative or from negative to positive.

We find points of inflection in a way similar to finding critical numbers. First, find of a function and solve for the x-values when is zero or undefined. These x-values are possible points of inflection. Next, draw a number line, mark the number line , and mark the x-values on the number line. We know that at these possible points of inflection is zero or undefined. Using the number line, we can find the sign changes for each of these points. If changes sign around the x-values on the number line, then that x-value is a point of inflection.

**Example:** Let us find the points of inflection of .**Solution:**We find the first derivative, .

Then we find the second derivative, .

Since is never undefined for this function, find the points of inflection by solving:

changes from negative to positive around -1. Therefore, the point of inflection for is (-1, 6).

**Two links you can check out for further information:**

http://www.math.hmc.edu/calculus/tutorials/extrema/

http://www.math.hmc.edu/calculus/tutorials/secondderiv/**Reminder: Crystal, you are up to post next.**

**Here are some pictures I took at the Huntington Gardens:**

## 1 Comments:

Thanks Jessica for posting such a coherent and easy to understand blog. I was lost before reading your blog on how second derivatives really worked. So thanks.

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